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10n^2-21n-1=0
a = 10; b = -21; c = -1;
Δ = b2-4ac
Δ = -212-4·10·(-1)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{481}}{2*10}=\frac{21-\sqrt{481}}{20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{481}}{2*10}=\frac{21+\sqrt{481}}{20} $
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